Terminate my application with exit code #1074
Description
Bug report from #1073
Discussed in #1073
Originally posted by nemliyartym April 28, 2023
Hi all. I would like to know how can I terminate my application with the exit codes I need. I have a simple smb module with a run function that calls shutdowner.Shutdown(fx.ExitCode(20)) with the code I need.
If in main I just call app.Run() then my app exits with code 0. Do I test it with echo$?. I changed Run to call Start+Done+Stop to try and get the exit code from Done, but that didn't work for me. I also tried to change Doneto Wait, but in this case, the application hangs on the channel of wait.
Please, tell me what am I doing wrong?)
main.go
func main() {
app := fx.New(
//fx.NopLogger,
//config.Module,
//logger.Module,
smb.Module,
)
//app.Run()
if err := app.Start(context.TODO()); err != nil {
fmt.Println(err)
}
done := app.Done()
fmt.Println(done)
// wait := app.Wait()
// sig := <-wait
// fmt.Println(sig.ExitCode)
if err := app.Stop(context.TODO()); err != nil {
fmt.Println(err)
}
}smb.go
type Smb interface {
}
type smb struct {
logger *zap.Logger
}
func NewSmb(logger *zap.Logger) Smb {
return &smb{logger: logger}
}
func Run(logger *zap.Logger, shutdowner fx.Shutdowner) error {
logger.Info("shutdowner")
//SET EXIT CODE
shutdowner.Shutdown(fx.ExitCode(20))
logger.Info("shutdowner2")
return nil
}
var Module = fx.Module("smb",
fx.Provide(NewSmb),
fx.Invoke(Run),
fx.Decorate(
func(log *zap.Logger) *zap.Logger {
return log.Named("smb")
},
),
)