Rational .sqrt() should return an empty list instead of raising an error when all=True #37153
Description
Steps To Reproduce
sage: K = QQ[I]
sage: K(3).sqrt(extend=False, all=True)
[]
sage: ZZ(3).sqrt(extend=False, all=True)
[]
sage: QQ(3).sqrt(extend=False, all=True)
---------------------------------------------------------------------------
ValueError Traceback (most recent call last)
Cell In [19], line 1
----> 1 QQ(Integer(3)).sqrt(extend=False, all=True)
File ~/sage/sage-10.2/src/sage/rings/rational.pyx:1971, in sage.rings.rational.Rational.sqrt()
1969 if non_square:
1970 if not extend:
-> 1971 raise ValueError("square root of %s not a rational number" % self)
1972 from sage.misc.functional import _do_sqrt
1973 return _do_sqrt(self, prec=prec, all=all)
ValueError: square root of 3 not a rational numberExpected Behavior
When the all=True param is set, when there are no sqrt an empty list should be returned:
sage: QQ(3).sqrt(extend=False, all=True)
[]Actual Behavior
When the all=True param is set, when there are no sqrt an empty list should be returned:
sage: QQ(3).sqrt(extend=False, all=True)
---------------------------------------------------------------------------
ValueError Traceback (most recent call last)
Cell In [19], line 1
----> 1 QQ(Integer(3)).sqrt(extend=False, all=True)
File ~/sage/sage-10.2/src/sage/rings/rational.pyx:1971, in sage.rings.rational.Rational.sqrt()
1969 if non_square:
1970 if not extend:
-> 1971 raise ValueError("square root of %s not a rational number" % self)
1972 from sage.misc.functional import _do_sqrt
1973 return _do_sqrt(self, prec=prec, all=all)
ValueError: square root of 3 not a rational numberAdditional Information
No response
Environment
- **OS**: MacOS
- **Sage Version**: 10.2Checklist
- I have searched the existing issues for a bug report that matches the one I want to file, without success.
- I have read the documentation and troubleshoot guide