Spent a lifetime on that because I had not noticed that I was first enumerating elements using a list L, then enumerating the same elements using {x:i for i,x in enumerate(L)}. And of course that was not the same ordering T_T

Nathann

CC: @videlec

Component: combinatorial designs

Author: Nathann Cohen

Branch/Commit: dee4275

Reviewer: Vincent Delecroix

Issue created by migration from https://trac.sagemath.org/ticket/16797