continue in while loop with break as last statement #190
Description
I have a while loop as follows which is used to read data from a socket:
class GameClient
...
receive: () =>
-- Receive data from the game server
data = ''
err = ''
-- Receive any data from the client
while true
block, err, partial = @_socket\receive(1024)
if block
data = data .. block
continue
if partial
data = data .. partial
break
-- Check for data received and add it to the data map
if data\len() > 0
return data
return nil
The code (receive method) compiles to the following lua:
...
receive = function(self)
local data = ''
local err = ''
while true do
local _continue_0 = false
repeat
local block, partial
block, err, partial = self._socket:receive(1024)
if block then
data = data .. block
_continue_0 = true
break
end
if partial then
data = data .. partial
end
break
_continue_0 = true
until true
if not _continue_0 then
break
end
end
if data:len() > 0 then
return data
end
return nil
end
Which in lua 5.2 raises a syntax error based on the following series of lines:
break
_continue_0 = true
until true
Error: Syntax error: ... 'until' expected (to close 'repeat' at line 19) near '_continue_0'
The workaround I'm currently using is to change my while loop (in moonscript) to:
while true
block, err, partial = @_socket\receive(1024)
if block
data = data .. block
continue
else
if partial
data = data .. partial
break
which compiles to to the following lua:
receive = function(self)
local data = ''
local err = ''
while true do
local _continue_0 = false
repeat
local block, partial
block, err, partial = self._socket:receive(1024)
if block then
data = data .. block
_continue_0 = true
break
else
if partial then
data = data .. partial
end
break
end
_continue_0 = true
until true
if not _continue_0 then
break
end
end
if data:len() > 0 then
return data
end
return nil
end