build: Drop endianess workaround #64
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This mirrors a change in leveldb: google/leveldb@201f522, now that compilers can better optimise the generic code.
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I cannot figure out the endianness of the resulting checksum. |
| std::memcpy(&result, buffer, sizeof(result)); | ||
| return result; | ||
| #endif // BYTE_ORDER_BIG_ENDIAN | ||
| return ((static_cast<uint16_t>(static_cast<uint8_t>(buffer[0]))) | |
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buffer is of type const uint8_t*.
buffer[0] is of type uint8_t.
Hence, the explicit conversion static_cast<uint8_t>(buffer[0]) is redundant.
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This mirrors a change in leveldb: google/leveldb@201f522, now that compilers can better optimise the generic code.