hannes.g...@gmail.com, 2008-01-23T10:32:30.000Z

When I try to parse an N3, I get an error when a literal contains a \t. But
\t is defined to be in N3 strings.

I suspect the failure is in n3proc's unquote:

>>> from rdflib.syntax.parsers.n3p.n3proc import unquote
>>> unquote("\t")
Traceback (most recent call last):
  File "", line 1, in 
  File "build/bdist.linux-i686/egg/rdflib/syntax/parsers/n3p/n3proc.py",
line 85, in unquote
rdflib.syntax.parsers.n3p.n3proc.ParseError: Illegal literal character: '\t'

Comment 1 by eike...@gmail.com
This is actually correct, I believe, since "\t" should be escaped as r"\t". For example unquote(r"\t") will give you 
"\t" -- and unquote("\t") (AKA an actual tab character) will give the above error.

In looking into this issue I did notice Literal's n3 method is not correctly escaping "\t". Literal("\t").n3() should be 
"\\t" which is the same as r"\t".


Comment 2 by eike...@gmail.com



Comment 3 by gromgull
Eikeon is right - this seem to work fine

{{{
g=rdflib.graph.Graph()
g.parse(StringIO.StringIO(r'  "Gunnar\tlikes chese". '),
format="n3")
print g.serialize()


  
    <_4:name>Gunnar likes chese
  

}}}